Monday Madness

3 min read

This thread's last reply is from February 8, 2011, 4:35 PM UTC. Advice, software, and links below may be out of date — treat specific steps and download links with caution.

Tomk

Post #16February 8, 2011, 12:59 AM UTC

Well done Jimbo1!
[external image: Posted Image]
Is, in fact, the solution!

jeffce

Post #17February 8, 2011, 1:13 AM UTC

I was thinking that any number with two (2 and 12) and then a variation of a number used with the two but without the four was 10. LOL Kind of dizzying as I sit here and try to type it LOL!!!!

jeffce

Post #18February 8, 2011, 1:15 AM UTC

Wow Great Job!!!!

Doug

Post #19February 8, 2011, 4:35 PM UTC

Nicely done, Jimbo1